Verified Answer :

\(a_1=\frac{24}{2^1}+4=16\\\\a_2=\frac{24}{2^2}+4=10\\\\a_3=\frac{24}{2^3}+4=7\\\\a_4=\frac{24}{2^4}+4=5.5\\\\a_5=\frac{24}{2^5}+4=4.75\\\\a_6=\frac{24}{2^6}+4=4.375\\\vdots\\a_n=\frac{24}{2^n}+4\)

A1=21+24/2!=16

Hope I helped

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