What is the solution to the rational inequality?
$\frac{4 x}{x-2} \leq \frac{3}{x-2}$
A$\left(-\infty, \frac{3}{4}\right) \cup[2, \infty)$
B$\left(-\infty, \frac{3}{4}\right] \cup(2, \infty)$
C$\left[\frac{3}{4}, 2\right)$
D$\left(\frac{3}{4}, 2\right]$
$\frac{4 x}{x-2} \leq \frac{3}{x-2}$
A$\left(-\infty, \frac{3}{4}\right) \cup[2, \infty)$
B$\left(-\infty, \frac{3}{4}\right] \cup(2, \infty)$
C$\left[\frac{3}{4}, 2\right)$
D$\left(\frac{3}{4}, 2\right]$