Verified Answer :

\(The\ distance\ between\ A(x_A;\ y_A)\ and\ B(x_B;\ y_B):\\\\d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}\)

\((5;\ 6);\ (5;\ 2),\ subtitute\\\\d=\sqrt{(2-6)^2+(5-5)^2}=\sqrt{(-4)^2+0^2}=\sqrt{16}=4\)