Answer: \(4.32\text{ mm}^2\)
Step-by-step explanation:
The area of rhombus is given by :-
\(\text{Area}=\dfrac{1}{2}\times d_1\times d_2\), where \(d_1\) and \(d_2\) are the diagonals of the rhombus.
Given: The diagonals of rhombus are 2.7 mm and 3.2 mm.
Then, the area of rhombus will be :-
\(\text{Area}=\dfrac{1}{2}\times 2.7\times 3.2\\\\\Rightarrow\text{Area}=4.32\text{ mm}^2\)
Therefore, the area of the rhombus = \(4.32\text{ mm}^2\)
