Answer:
18 inches
Step-by-step explanation:
We have that,
Length of the photo, \(L_{s}\) = 6 inches and Width of the photo, \(W_{s}\) = 4 inches.
Now, the photo is enlarged with the new width i.e. \(W_{l}\) is 12 inches.
Let, the length of the enlarged photo i.e. \(L_{l}\) be x inches.
Since, the ratio between length and width remains same, we have the relation,
\(\frac{L_{s}}{W_{s}}=\frac{L_{l}}{W_{l}}\)
i.e. \(\frac{6}{4}=\frac{x}{12}\)
i.e. \(\frac{3}{2}=\frac{x}{12}\)
i.e. \(x=\frac{3\times 12}{2}\)
i.e. \(x=\frac{36}{2}\)
i.e. \(x=18\)
Hence, the length of enlarged photo is 18 inches.
