Answer
0.43
Explanation
Remember that \(RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}\)
Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so \(Frecuency=6\). Now, the sum of all frequencies will be the sum of all the 10th graders, so \(SumOfAllFrecuencies=6+8=14\). Let's replace the values:
\(RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}\)
\(RelativeFrecuency=\frac{6}{14}\)
\(RelativeFrecuency=0.4285\)
And rounded to the nearest hundredth:
\(RelativeFrecuency=0.43\)
