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Maccy Maccy
  • 16-03-2015
  • Mathematics
Answered

let r>0 -π<θ<π be real. Calculate all the values of


\(Re( \frac{ln(z)}{z})\)


where \(z=r(cos(\theta)+sin(\theta))\).

Verified Answer :

Hippalectryon
Hippalectryon Hippalectryon
  • 16-03-2015

For a real z, ln(z)/z is always a real number, so the Re() is quite useless.

Thus we just need to write \(ln(z)/z=ln(r)+ln(\cos(\theta)+\sin(\theta))\), and we can't simplify any more.

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