Answered

ten plus eight times a number a equals eleven times another number d minus six solve for a

Verified Answer :

TecciAmanda07

So your equation would be 8a+10=11d-6
First: you would combine like terms so normally you would take away the smaller number. So to cancel out the negative 6 you added you add positive six to the negative 6 so you would get 0 and whatever you do to one side you have to do to the other so you would do 10 + 6. Your new equation would be 8a+16=11d. Now you do -16 to both sides. So your new equation would be 8a= 11d - 16. Now you divide by 8. So your final equation would be a=11d-2.

Answer:

\(a=\frac{11d-16}{8}\)

Step-by-step explanation:

We have been given a word phrase. We are asked to write an equation and solve for 'a'.

Eight times the number 'a' would be \(8a\).

Ten plus eight times a number 'a' would be \(10+8a\).

Eleven times another 'd' would be \(11d\).

Eleven times another 'd' minus six would be \(11d-6\).

Equate both expression:

\(10+8a=11d-6\)

\(10-10+8a=11d-6-10\)

\(8a=11d-16\)

\(\frac{8a}{8}=\frac{11d-16}{8}\)

\(a=\frac{11d-16}{8}\)

Therefore, the value of 'a' is \(\frac{11d-16}{8}\).

Related Questions