For this case, the first thing we must do is define variables.
We have then:
b: number of booths
t: number of tables
We write the expression that models the problem.
We know that 5 of the booths are full.
Therefore, the available space is:
\(4 (b-5) + 6t = 100\)
Rewriting we have:
\(4b - 20 + 6t = 100
4b + 6t = 100 + 20
4b + 6t = 120\)
Simplifying we have:
\(2b + 3t = 60\)
Answer:
An expression that matches the situation is:
\(2b + 3t = 60\)
