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  1. The 600 N ball shown is suspended on a string AB and rests against a frictionless vertical wall.
    The string makes an angle of 30° with the wall. The magnitude of the tension force of the string is:
    (a) 400 √√3 N (b) 1200 N (c) 400 √2 N
    (d) 2400 N
    ​

Verified Answer :

MathPhys

Answer:

(a) 400√3 N

Explanation:

By drawing a free body diagram, which is a diagram of all the forces acting on the ball, we can balance the forces and solve for the tension. There are three forces on the ball:

  • Weight force mg pulling down
  • Tension force T pulling up 30° from the vertical
  • Normal force N pushing horizontally

Summing the forces in the vertical direction:

∑F = ma

T cos 30° − mg = 0

T cos 30° = mg

T = mg / cos 30°

Plug in values:

T = (600 N) / cos 30°

T = (600 N) / (√3 / 2)

T = 1200 N / √3

T = 400√3 N

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