The principal represents an amount of money deposited in a savings account subject to compound interest at the given rate. Answer parts (a) and (b).




Principal
RateCompoundedTime

\$3000
2.5\%monthly5 years





AFind how much money there will be in the account after the given number of years.



The amount of money in the account after 5 years is \$ □ .

(Round to the nearest hundredth as needed.)

Verified Answer :

  • Identify the variables from the problem: Principal \(P = \$3000\), annual rate \(r = 0.025\), compounding periods per year \(n = 12\), and time \(t = 5\) years.
  • Apply the compound interest formula \(A = P(1 + \frac{r}{n})^{nt}\).
  • Compute the values: \(A = 3000(1 + \frac{0.025}{12})^{60}\).
  • Determine the final amount, rounded to the nearest cent: \(\boxed{\$3399.00}\).

Explanation

  1. Analysis and Problem Setup

We are tasked with calculating the final balance in a savings account after a specific time period under compound interest. We are given the following information:

  • Principal amount (\(P\)): \(\$3000\)
  • Annual interest rate (\(r\)): \(2.5\% = 0.025\)
  • Compounding frequency (\(n\)): monthly, which is \(12\) times per year
  • Time (\(t\)): \(5\) years

The formula for the total amount (\(A\)) in an account with interest compounded \(n\) times per year is:
\[A = P\left(1 + \frac{r}{n}\right)^{nt}\]

  1. Substituting Values and Simplifying

Using the identified values, we substitute them into the compound interest formula:
\[A = 3000 \times \left(1 + \frac{0.025}{12}\right)^{12 \times 5}\]

First, we simplify the terms within the exponent and the parentheses:

  • The exponent: \(12 \times 5 = 60\)
  • The rate per period: \(\frac{0.025}{12} \approx 0.00208333333\)
  • The base of the exponent: \(1 + \frac{0.025}{12} \approx 1.00208333333\)

Now, calculate the expression:
\[A = 3000 \times (1.00208333333)^{60}\]

  1. Final Calculation and Rounding

Calculating the power \((1.00208333333)^{60}\) gives approximately \(1.13300112\).

Multiplying this by the principal amount:
\[A = 3000 \times 1.13300112 \approx 3399.0033656\]

Rounding the result to the nearest hundredth (as is standard for financial currency calculations), we get:
\[A \approx \$3399.00\]

Examples

Understanding compound interest is a vital skill for personal finance. For instance, if you decide to start a savings account at age 20 with a modest deposit of \(\$3000\), seeing how that money grows over time due to compound interest helps you appreciate the power of starting early. Even with a relatively low interest rate, the compounding effect—where you earn interest on your previous interest—ensures your money works for you, demonstrating why long-term saving and investing are cornerstones of financial health.