- Recognize the logarithmic property \(\log_b(A) = C \iff b^C = A\).
- Identify the components: \(b = 3\), \(A = x + 5\), and \(C = 2\).
- Convert the equation to the equivalent exponential form \(3^2 = x + 5\).
- The correct choice is \(\boxed{3^2 = x + 5}\).
Explanation
- Understanding Logarithmic Equations
The given equation is \(\log_3(x+5) = 2\). We know that a logarithmic expression of the form \(\log_b(A) = C\) is equivalent to the exponential expression \(b^C = A\), provided that \(b > 0, b
eq 1,\) and \(A > 0\). This definition allows us to transform logarithmic equations into algebraic equations that are often easier to solve.
- Transforming the Equation
In the equation \(\log_3(x+5) = 2\), we can identify the components based on the standard logarithmic form \(\log_b(A) = C\):
- The base \(b\) is \(3\).
- The argument \(A\) is \(x + 5\).
- The value \(C\) is \(2\).
By substituting these values into the equivalent exponential form \(b^C = A\), we obtain the equation \(3^2 = x + 5\).
- Selecting the Correct Equation
Now we compare our derived equation, \(3^2 = x + 5\), with the given options:
- \(3^2 = [\log_3(x+5)]^3\)
- \(2^3 = [\log_3(x+5)]^2\)
- \(3^2 = x + 5\)
- \(2^3 = x + 5\)
Our result perfectly matches the third option. Thus, the equation equivalent to \(\log_3(x+5) = 2\) is \(3^2 = x + 5\).
Examples
Logarithmic properties are fundamental in many real-world applications where quantities change exponentially, such as calculating the pH of a solution, measuring sound intensity in decibels, or analyzing the growth of populations or investments. Understanding how to convert logarithmic expressions to exponential ones is a crucial skill for solving these types of equations. For example, if you are determining the time \(t\) it takes for an investment to grow to a certain amount using the formula \(A = P(1+r)^t\), you would take the logarithm of both sides to isolate \(t\), then potentially convert back to exponential form for calculation.