Find the quotients.


A$\frac{2}{5} \div \frac{3}{4}$
B$\frac{9}{4} \div\left(\frac{-3}{4}\right)$
C$\left(\frac{-5}{7}\right) \div\left(\frac{-1}{3}\right)$
D$\left(\frac{-5}{3}\right) \div \frac{1}{6}$

Verified Answer :

  • To divide fractions, multiply the first fraction by the reciprocal of the second: \(\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}\).
  • Part a: \(\frac{2}{5} \times \frac{4}{3} = \boxed{\frac{8}{15}}\)
  • Part b: \(\frac{9}{4} \times \frac{4}{-3} = \boxed{-3}\)
  • Part c: \(\frac{-5}{7} \times \frac{3}{-1} = \boxed{\frac{15}{7}}\)
  • Part d: \(\frac{-5}{3} \times \frac{6}{1} = \boxed{-10}\)

Explanation

  1. Understanding the Division Rule for Fractions

To divide two fractions, we use the rule that dividing by a fraction is equivalent to multiplying by its reciprocal. For any two fractions \(\frac{a}{b}\) and \(\frac{c}{d}\), where \(\frac{c}{d} eq 0\), the division is defined as \[\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c} = \frac{ad}{bc}.\] We apply this rule to each part of the problem, ensuring that we simplify the resulting fractions and correctly handle the signs of the quotients.

  1. Solving Part (a)

For part (a), we have \(\frac{2}{5} \div \frac{3}{4}\). The reciprocal of \(\frac{3}{4}\) is \(\frac{4}{3}\). Thus, the division becomes:
\[\frac{2}{5} \times \frac{4}{3} = \frac{2 \times 4}{5 \times 3} = \frac{8}{15}.\]
This fraction cannot be simplified further.

  1. Solving Part (b)

For part (b), we have \(\frac{9}{4} \div \left(\frac{-3}{4}\right)\). The reciprocal of \(\frac{-3}{4}\) is \(\frac{4}{-3}\). Thus, the division becomes:
\[\frac{9}{4} \times \left(\frac{4}{-3}\right) = \frac{9 \times 4}{4 \times -3} = \frac{36}{-12}.\]
Dividing 36 by -12 gives \(-3\). So, the quotient is \(-3\).

  1. Solving Part (c)

For part (c), we have \(\left(\frac{-5}{7}\right) \div \left(\frac{-1}{3}\right)\). The reciprocal of \(\frac{-1}{3}\) is \(\frac{3}{-1}\). Thus, the division becomes:
\[\left(\frac{-5}{7}\right) \times \left(\frac{3}{-1}\right) = \frac{-5 \times 3}{7 \times -1} = \frac{-15}{-7}.\]
Since a negative divided by a negative is positive, the quotient is \(\frac{15}{7}\).

  1. Solving Part (d)

For part (d), we have \(\left(\frac{-5}{3}\right) \div \frac{1}{6}\). The reciprocal of \(\frac{1}{6}\) is \(\frac{6}{1}\). Thus, the division becomes:
\[\left(\frac{-5}{3}\right) \times \frac{6}{1} = \frac{-5 \times 6}{3 \times 1} = \frac{-30}{3}.\]
Dividing -30 by 3 gives \(-10\). So, the quotient is \(-10\).

Examples

When dividing items or resources, such as splitting a bulk order of materials into smaller packages, understanding how to handle fractions is crucial. For example, if you have \(\frac{10}{3}\) kilograms of sand and need to divide it into bags of \(\frac{2}{3}\) kilograms each, you would calculate \(\frac{10}{3} \div \frac{2}{3} = \frac{10}{3} \times \frac{3}{2} = 5\), meaning you can fill exactly 5 bags. Mastering fraction division ensures precise resource allocation and management in various practical situations.