Landon143 Landon143

01-05-2014
Mathematics

Answered

Prove identity tan 3x−tan 2x−tanx = tan 3xtan 2xtanx

Verified Answer :

crisforp crisforp

02-05-2014

tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)(tan b) ];

let be a = 2x and b = x;

=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)(tan x) ] => (tan 3x)[ 1 - (tan 2x)(tan x) ] =

tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.

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