- Identify the perfect cube factors in the coefficient \(250\) and the variable \(y^8\).
- Recognize that \(250 = 5^3 \cdot 2\) and \(y^8 = (y^2)^3 \cdot y^2\).
- Apply the radical rule \(\sqrt[3]{abc} = \sqrt[3]{a} \cdot \sqrt[3]{b} \cdot \sqrt[3]{c}\) to pull out the perfect cube terms.
- The final simplified expression is \(\boxed{5y^2 \sqrt[3]{2y^2}}\).
Explanation
- Analysis of the Radicand
To simplify the expression \(\sqrt[3]{250y^8}\), we begin by examining the components inside the cube root. The expression consists of a numerical coefficient \(250\) and a variable part \(y^8\). A cube root \(\sqrt[3]{x}\) is equivalent to taking the power of \(1/3\). Our objective is to factor out any perfect cubes from the radicand, as they can be extracted from the radical.
- Factoring the Terms
First, we factor the numerical coefficient \(250\). We look for the largest perfect cube factor:
\[250 = 125 \times 2 = 5^3 \times 2.\]
Next, we factor the variable term \(y^8\). We want to express the exponent as a multiple of 3 plus a remainder:
\[y^8 = y^6 \times y^2 = (y^2)^3 \times y^2.\]
These factorizations allow us to separate the perfect cube components from the rest of the expression.
- Simplification of the Radical
We rewrite the original expression by substituting our factors back into the cube root:
\[\sqrt[3]{250y^8} = \sqrt[3]{5^3 \cdot 2 \cdot (y^2)^3 \cdot y^2}.\]
Using the property of radicals \(\sqrt[3]{abc} = \sqrt[3]{a} \cdot \sqrt[3]{b} \cdot \sqrt[3]{c}\), we can distribute the cube root:
\[\sqrt[3]{5^3} \cdot \sqrt[3]{(y^2)^3} \cdot \sqrt[3]{2y^2}.\]
Evaluating the perfect cubes \(\sqrt[3]{5^3} = 5\) and \(\sqrt[3]{(y^2)^3} = y^2\), we obtain:
\[5y^2 \sqrt[3]{2y^2}.\]
This is the fully simplified form of the given expression.
Examples
Simplifying radical expressions is a fundamental skill in algebra, useful for solving equations, working with geometric formulas (such as the volume of a sphere or the length of a space diagonal), and engineering designs. For example, if you need to calculate the side length of a cube with volume \(250y^8\), you would need to compute \(\sqrt[3]{250y^8}\), which simplifies to \(5y^2\sqrt[3]{2y^2}\). This makes it easier to estimate the value or use it in further calculations.