Hello,
\(\sqrt{2x+4}- \sqrt{x} =2\\
==\ \textgreater \ \sqrt{2x+4}=2+ \sqrt{x}\\
==\ \textgreater \ 2x+4=4+4 \sqrt{x} +x \\
==\ \textgreater \ x=4 \sqrt{x} \\
==\ \textgreater \ x^2=16*x\\
==\ \textgreater \ x^2-16x=0\\
==\ \textgreater \ x(x-16)=0\\
==\ \textgreater \ x=0 \ or \ x=16\\
Answer B\)
