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Clouston174
Clouston174 Clouston174
  • 24-08-2015
  • Mathematics
Answered

What are the zeroes of f(x) = x2 - 6x + 8? (4 points) x = -4, 2 x = -4, -2 x = 4, 2 x = 4, -2

Verified Answer :

Anonymous Anonymous
  • 24-08-2015

\(f(x)=x^2-6x+8\\\\the\ zeros:f(x)=0\to x^2-6x+8=0\\\\x^2\underbrace{-4x-2x}_{=-6x}+8=0\\\\x\cdot x-x\cdot4-2\cdot x-2\cdot(-4)=0\\\\x(x-4)-2(x-4)=0\\\\(x-4)(x-2)=0\iff x-4=0\ or\ x-2=0\\\\therefore\\\\\boxed{x=4\ or\ x=2}\)

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kaleag1205
kaleag1205 kaleag1205
  • 30-04-2021

Answer:

The answer is C.

Step-by-step explanation:

I took the test and got it right

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