radomes.openskiesproject.org
Stas747 Stas747
  • 04-05-2015
  • Mathematics
Answered

How do I solve this.


Log 5x = log (2x+9)

Verified Answer :

konrad509
konrad509 konrad509
  • 04-05-2015

\(D:5x\ \textgreater \ 0 \wedge 2x+9\ \textgreater \ 0\\ D:x\ \textgreater \ 0 \wedge 2x\ \textgreater \ -9\\ D:x\ \textgreater \ 0 \wedge x\ \textgreater \ -\dfrac{9}{2}\\ D:x\ \textgreater \ 0\\\\ \log5x=\log(2x+9)\\ 5x=2x+9\\ 3x=9\\ x=3\)

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