Verified Answer :

To solve equations with variables, we useĀ inverse operations.
Inverse operations are operations that cancel each other out.
(plus and minus, multiply and divide)

Say we had \(x-3=6\).
According to the addition property of equality, we could add 3 to each side of that equation and it would still be equal.
\(x-3+3=6+3\)
This would cancel out the -3 and leave us with just \(x=9\).

Question 1) Solve \(2(n-7)+3=9\).

Let's just start cancelling things out. Doesn't matter what order.

\(2(n-7)+3=9 \\ 2(n-7)+3-3=9-3\\ 2(n-7)=6 \\\\\ \frac{2(n-7)}2=\frac{6}2\ -7=3\\\ -7+7=3+7\\\boxed{n=10}\)

Question 2) Solve \(4h+7h-16=6\).

You can add \(4h\) and \(7h\) together to get \(11h\). The h acts sort of like a unit in that case, like 4 feet + 7 feet = 11 feet.

\(11h-16=6\\11h-16+16=6+16\\11h=22\\\\\frac{11h}{11}=\frac{22}{11}\\\boxed{h=2}\)

2 (n-7) +3=9
remove ( ) and distribute
2n-14+3=9
combine like terms
2n-11=9
add 11 to both sides
2n=20
n=10

4h+7h-16=6
combine like terms
11h-16=6
add 16 to both sides
11h=22
h= 2

hope this helps