Answer:
\(\frac{2}{3}\) feet.
Step-by-step explanation:
We have been given that area of a triangle is \(\frac{2}{5}\text{ ft}^2\). We are asked to find the length of the base of the triangle.
\(A=\frac{1}{2}bh\), where,
A= Area of the triangle,
b = Base of the triangle,
h = height of the triangle.
Upon substituting our given values in are of triangle formula we will get,
\(\frac{2}{5}=\frac{1}{2}*b*\frac{6}{5}\)
\(\frac{2}{5}=b*\frac{3}{5}\)
Upon multiplying both sides of our equation by 5/3 we will get,
\(\frac{2}{5}*\frac{5}{3}=b*\frac{3}{5}*\frac{5}{3}\)
\(\frac{2}{3}=b\)
Therefore, the length of the base of our given triangle will be \(\frac{2}{3}\) feet.
