Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is divisible by 3.
There are 30 total integers. 10 of these will be divisible by 3 (all multiples of 3 between 3 and 30). So the probability of getting an integer evenly divisible by 3 is \(\dfrac{10}{30}=\dfrac13\).
Answer:
probability that the integer chosen is divisible by 3 is \(\frac{1}{3}\).
Step-by-step explanation:
Given : An integer be chosen at random from the integers 1 to 30 inclusive.
To find : Find the probability that the integer chosen is divisible by 3.
Solution : We have integers 1 to 30.
We need to find probability that the integer is divisible by 2.
We know that multiple of 3 is divisible by 3
All multiple of 3 from 1 to 30 ( 3,6,9,12,15,18,21,24,27,30)
Total multiple of 3 from 1 to 30 = 10 .
Probability = \(\frac{Favourble\ outcome}{Total\ number\ of\ outcome}\)
Probability = \(\frac{10}{30}\)
Probability = \(\frac{1}{3}\).
Therefore, probability that the integer chosen is divisible by 3 is \(\frac{1}{3}\).