Answer:
Option B
Step-by-step explanation:
Equation of a parabola is given as y = -4x² + 8x + 12
We have to find the x-intercepts, of the parabola.
for any point on x-axis y coordinates will be zero.
So put placing y = 0 in the equation.
0 = -4x² + 8x + 12
-4(x² - 2x - 3) = 0
x² - 2x - 3 = 0
x² - 3x + x - 3 = 0
x ( x-3) + 1( x - 3) = 0
( x+1 ) ( x - 3 ) = 0
( x + 1 ) = 0 ⇒ ( x = -1 )
( x - 3 ) = 0 ⇒ ( x = 3 )
points on x-axis will be ( -1, 0 ) & ( 3, 0 )
Option B is the answer.
