Aisha owns an apparel store. She bought some shirts and jeans from a wholesaler for $3,900. Each shirt cost $12 and each pair of jeans cost $28. If she sold the shirts at 70% profit and jeans at 125% profit, her total profit was $3,885. How many shirts and jeans did she buy from the wholesalers?

Let the number of shirts be x, and the jeans be y.

Total cost of shirts = 12x
Total cost of Jeans = 28y

This means that: 12x + 28y = 3900..........(a)

Selling price for Shirts 70% profit, means = 100% + 70% = 170% of the cost price

170/100 12x = 1.712x = 20.4x

Selling price for Jeans 125% profit, means = 100% + 125% = 225% of the cost price

225/100 28y = 2.2528y = 63y

Total profit = 3885, remember total cost = 3900

Total selling price = 3885 + 3900 = 7785

20.4x + 63y = 7785..........(b)

12x + 28y = 3900.............(a)

20.4x + 63y = 7785...........(b)

Solving the simultaneous equation with a programmable calculator:

x = 150, y = 75

150 shirts and 75 jeans.

calculista calculista · Answer 2 · 2018-09-06T16:36:08-04:00

Let

x-------> the number of shirts

y------> the number of jeans

we know that

$12x+28y=3,900$ -------> equation $1$

If she sold the shirts at $70\%$ profit and jeans at $125\%$ profit, her total profit was $\$3,885$

so

$1.7*(12x)+2.25*(28y)=3,900+3,885$

$20.4x+63y=7,785$ -------> equation $2$

we have the following system of equations

$12x+28y=3,900$ -------> equation $1$

$20.4x+63y=7,785$ -------> equation $2$

using a graph tool

see the attached figure

The solution of the system is the intersection both graphs

the solution is the point $(150,75)$

that means

$x=150\ shirts\\y=75\ jeans$

therefore

the answer is

the number of shirts is $150$

the number of jeans is $75$