A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and vertical components of the skier's displacement?
Opposite from the angle is 134.7905
Adjacent to the angle is 192.5007
Explanation:
It is given that,
Height of the mountain, h = 235 m
A skier descends a mountain at an angle of 35º to the horizontal, \(\theta=35^{\circ}\)
We need to find the horizontal and vertical components of the skier's displacement.
Horizontal component, \(x=h\ cos\theta\)
\(x=235\ cos(35)=192.5\ m\)
Vertical component, \(y=h\ sin\theta\)
\(y=235\ sin(35)=134.79\ m\)
Hence, this is the required solution.