For y = 4x + 2x2 – x3, show how to find the value for y, when x = 2. Show your work
If you would like to find the value of y for x = 2, you can do this using the following steps:
y = 4 x + 2 x^2 – x^3
x = 2
y = 4 2 + 2 2^2 - 2^3 = 8 + 2 * 4 - 8 = 8 + 8 - 8 = 8
The correct result would be y = 8.
\(Start \ with \ the \ original \ equation\)
\(y=4x+2x^2-x*3\)
\(Let \ x=2\)
\(y=4*2+2*2^2-2*3\)
\(\fbox{y = 10}\)