Answer:
The factors of equation \(18x^2-21x-15\) is \(=3((3x-5)(2x+1))\)
Step-by-step explanation:
Given : Equation \(18x^2-21x-15\)
We have to factorize the given equation \(18x^2-21x-15\)
Consider the given equation\(18x^2-21x-15\)
Taking 3 common from each term, we have,
\(=3\left(6x^2-7x-5\right)\)
We will solve the given equation using middle term split method,
-7x can be written as 3x -10x
Equation becomes,
\(=3(6x^2+3x-10x-5)\)
Taking 3x common from first two term and -5 common from last two terms, we have,
\(=3(3x(2x+1)-5(2x+1))\)
Taking (2x+1) common, we have,
\(=3((3x-5)(2x+1))\)
Thus, The factors of equation \(18x^2-21x-15\) is \(=3((3x-5)(2x+1))\)
