Solve.

{d+e=2d−e=4

Use the substitution method.

There are an infinite number of solutions.

There is no solution.

The solution is (3, −1).

The solution is (5, 1).

Question

22-02-2017
Mathematics

Answered

Solve.

{d+e=2d−e=4

Use the substitution method.

There are an infinite number of solutions.

There is no solution.

The solution is (3, −1).

The solution is (5, 1).

Verified Answer :

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OrethaWilkison OrethaWilkison · Answer 1 · 2019-01-24T12:02:21-05:00

Answer:

Option C is correct.

The solution is (3, -1)

Step-by-step explanation:

Substitution

Given the system of equation:

\(d+e = 2\) ......[1]

\(d-e = 4\) ......[2]

We can write equation [2] as;

d = e +4 ....[3]

Using substitution method;

Substitute the value of d in equation [1] we have;

\(e+4+e = 2\)

Combine like terms;

\(2e +4 = 2\)

Subtract 4 from both sides, we get

2e = -2

Divide both sides by 2 we get;

e = -1

Substitute the value of e = -1 in [1] we have;

d +(-1) = 2

d -1 = 2

Add 1 to both sides of an equation;

d = 3

Therefore, the solution for the given system of equation is, (3, -1)

cainbibie3 cainbibie3 · Answer 2 · 2021-02-03T13:26:04-05:00

Answer:

Option C is correct.

The solution is (3, -1)

Step-by-step explanation:

Substitution

Given the system of equation:

......[1]

......[2]

We can write equation [2] as;

d = e +4 ....[3]

Using substitution method;

Substitute the value of d in equation [1] we have;

Combine like terms;

Subtract 4 from both sides, we get

2e = -2

Divide both sides by 2 we get;

e = -1

Substitute the value of e = -1 in [1] we have;

d +(-1) = 2

d -1 = 2

Add 1 to both sides of an equation;

d = 3

Therefore, the solution for the given system of equation is, (3, -1)

Solve.{d+e=2d−e=4Use the substitution method.There are an infinite number of solutions.There is no solution.The solution is (3, −1).The solution is (5, 1).

Verified Answer :

Related Questions

Solve.

{d+e=2d−e=4

Use the substitution method.

There are an infinite number of solutions.

There is no solution.

The solution is (3, −1).

The solution is (5, 1).