Lostgirl21
Answered

a bullet is fired into the air with an initial velocity of 1600 f/s at an angle for 45 dgrees from the horizontal. What is the horizontal distance traveled by the bullet in 2 seconds?

Verified Answer :

so you know the horizontal acceleration is zero

integrating this you can find the horizontal velocity as

vh=Vcos(α)

V = initial velocity 1200 ft/sec

the angle is 45 so you have

vh=1200cos(45)

if you integrate this equation with respect to time (t) you get the horizontal displacement equation.

the initial condtions for the horizontal displacement seem to bet at t = 0, x = 0

then when you get the equation, just substitute t = 2 and evaluate

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