Answer: \(4.0\times 10^{24}\) mercury atoms
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number \(6.023\times 10^{23}\) of particles.
1 mole of mercury \(Hg\) contains=\(6.022\times 10^{23}\) atoms
Thus 6.7 moles of mercury \(Hg\) contains=\(\frac{6.022\times 10^{23}}{1}\times 6.7=4.0\times 10^{24}\) atoms
Thus there are \(4.0\times 10^{24}\) mercury atoms are in 6.7 mol of mercury.