Answer:
\(x=\frac{5}{3}\) and \(x=-2\)
Step-by-step explanation:
The given equation is:
\(6x^2+2x-20=0\)
which can be simplified as:
\(3x^2+x-10=0\)
Factorizing the above equation, we get
\(3x^2+6x-5x-10=0\)
\(3x(x+2)-5(x+2)=0\)
\((3x-5)(x+2)=0\)
Thus, Using the zero product property ,the solutions of the given equations are:
\(x=\frac{5}{3}\) and \(x=-2\)
