mass = volume density = 1.00 mL 0.789 g/mL = 0.789 g
The relative molecular mass of ethanol can be calculated by adding the relative atomic masses of all the atoms within its structure (C2H5OH):
(12.011 g/mol 2) + (15.999 g/mol 1) + (1.0079 g/mol 6) = 46.068 g/mol
2 Carbon 1 Oxygen 6 Hydrogen
This can be used to find the number of moles of ethanol:
moles = mass / rmm = 0.789 g / 46.068 g/mol = 0.0171 mol (3 sig. fig.)
Using Avogadro's constant, the number of molecules within 1 mole of substance, the number of molecules within 1 mL of ethanol can be found:
no. molecules = moles Avogadro constant
= 0.0171 mol (6.02210^23 1/mol)
= 1.03*10^22 molecules