what is the molality of a solution that is obtained by dissolving 2.922 g of nacl into 1000.0 g of water if the molar mass of nacl is 58.44 g/mol? use molality=moles of solute/kilograms of solvent

Verified Answer :

1000cm = 1 mol
2.922 g of nacl / 58.44 = 0.05 * 1000 = 50 g/mol

Answer: 0.05 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

\(Molality=\frac{n\times 1000}{W_s}\)

where,

n = moles of solute

To calculate the moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{2.922}{58.44}=0.05moles\)

\(W_s\) = weight of solvent in g=1000 g

Molality =\(\frac{n\times 1000}{W_s}=\frac{0.05\times 1000}{1000}=0.05m\)

Thus molality of the solution is 0.05m