what is the molality of a solution that is obtained by dissolving 2.922 g of nacl into 1000.0 g of water if the molar mass of nacl is 58.44 g/mol? use molality=moles of solute/kilograms of solvent
Answer: 0.05 m
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
\(Molality=\frac{n\times 1000}{W_s}\)
where,
n = moles of solute
To calculate the moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{2.922}{58.44}=0.05moles\)
\(W_s\) = weight of solvent in g=1000 g
Molality =\(\frac{n\times 1000}{W_s}=\frac{0.05\times 1000}{1000}=0.05m\)
Thus molality of the solution is 0.05m