Verified Answer :

\(\bf \begin{array}{cccccclllll}&\\ \textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\&\\ \textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\&\\ y&=&{{ k}}&\cdot&x&\\ &\\ && y={{ k }}x&\\ \end{array}& \\\\\\ \textit{we know that } \begin{cases} y=12\\ x=1.2 \end{cases}\implies y=kx\implies 12=k\cdot 1.2\)

solve for "k" to find "k", or the "constant of variation"

nobrains

Direct variation is expressed as y = kx, where k is the constant of variation.

You are given that y = 12 and x = 1.2, so you can find k by substituting this into the direct variation equation:
y = kx
(12) = k(1.2)
k = 10

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