Verified Answer :

wolf1728

We can factor the equation into:
(x-10)*(x-3)
Therefore the roots are:
X = 10
X = 3

Answer:

Option B and D are correct.

x = 3 and x = 10

Step-by-step explanation:

Given the functions:

\(f(x) =x^2-13x+30\)

Split the middle terms:

\(f(x) =x^2-10x-3x+30\)

Take out the common factor:

\(f(x) =x(x-10)-3(x-10)\)

⇒\(f(x) =(x-10)(x-3)\)

To find the zeroes of this function f(x).

Equate f(x) = 0

then;

\((x-10)(x-3)=0\)

By zero product property: if ab=0 then a=0 or b = 0

then;

x-10 = 0 and x-3 = 0

⇒x = 10 and x = 3

Therefore, the zeros of the given function are: x = 10 and 3