you slide across a wooden floor in your socks. there is a normal force of 1033 n acting on you, and the coefficient of kinetic friction is 0.21. what is the force of friction acting on you as you slide?
While you stand up, the force on you is your weight (w). The friction force when you slide is:
\(F_R = \mu \cdot w = 0.21\cdot 1033\ N = \bf 216.93\ N\)
Answer:
216.93 N
Explanation:
An object slides over a surface when sliding force due to friction acts.
The sliding force of friction \((F_s)\) and normal force (N) are related as:
\(F_s = \mu _s N\)
Where, \(\mu_s\) is coefficient of kinetic friction.
Given:
N = 1033 N
\(\mu_s = 0.21\\ \Rightarrow F_s = 0.21 \times 1033 N = 216.93 N\)
Thus, the force of friction would be 216.93.