An investment account earns 4% per year compounded annually if the initial investment was $4000 how much is the account after three years? Round your answer to the nearest dollar
compounded annualy makes it easier
\(A=P(1+r)^t\)
A=future amount
P=present amount
r=rate in decimal
t=time in years
given
P=4000
r=4%=0.04
t=3
\(A=4000(1+0.04)^3\)
\(A=4000(1.04)^4\)
A=4499.456
round
about $4499 in the account after 3 years
\(4000 * (\frac{100+4}{100} )^{3} = 4499.46\)
To the nearest dollar, it's $4499.