The circumference of the base of a cone is 24π inches. The slant height of the cone is 20 inches. What is the surface area of the cone? Express the answer in terms of π.
the formula for surface area of a cone = 2pi rh
the radius of the base = 12inches
by the pythagoras theorem, 400 - 144 = 256 =16^2
therefore the height of the cone = 16inches
the surface area of the cone= 16 × 24pi
=384pi inches
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The surface area of the cone is 384π square inches whose circumference of the base of a cone is 24π and the slant height of the cone is 20 inches.
It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.
We have:
circumference of the base of a cone = 24π inches
The slant height of the cone = 20 inches
The circumference of the base circle = 2πr where r is the radius.
2πr = 24π
r = 12 inches
We know the surface area of the cone is given by:
S = πr² + πrl
Where l is the slant height of the cone
S = π(12)² + π(12)(20)
S = 144π + 240π
S = 384π square inches.
Thus, the surface area of the cone is 384π square inches.
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