Answer: The mass of copper(II)sulfate are, 89.6 grams
Explanation: Given,
Molecules of \(CuSO_4\) = \(3.36\times 10^{23}\)
Molar mass of \(CuSO_4\) = 160 g/mole
First we have to calculate the moles of \(CuSO_4\).
As, \(6.022\times 10^{23}\) number of \(CuSO_4\) atoms present in 1 mole of \(CuSO_4\)
So, \(3.36\times 10^{23}\) number of \(CuSO_4\) atoms present in \(\frac{3.36\times 10^{23}}{6.022\times 10^{23}}=0.56\) mole of \(CuSO_4\)
Now we have to calculate the mass of \(CuSO_4\)
\(\text{Mass of }CuSO_4=\text{Moles of }CuSO_4\times \text{Molar mass of }CuSO_4\)
\(\text{Mass of }CuSO_4=(0.56mole)\times (160g/mole)=89.6g\)
Therefore, the mass of copper(II)sulfate are, 89.6 grams
