Brass is an alloy made from copper and zinc. A 0.59 kg brass sample at 90.0 C is dropped into 2.80 kg of water at 5.0 C. If the equilibrium temperature is 6.8C, what is the specific heat capacity of brass?

Since no heat is lost to the surroundings, the change in thermal energy of the brass piece and the water sample have have the same magnitude:

m_brass ∙ c_brass ∙ ∆T_brass = m_water ∙ c_water ∙ ∆T_water

=>

c_brass = c_water ∙ (m_water/m_brass) ∙ (∆T_water/∆T_brass)
= 4186J/kg°C ∙ (2.8kg/0.59kg) ∙ ((6.8°C - 5°C) / (98°C - 6.8°C))
= 392J/kg

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Cricetus Cricetus · Answer 2 · 2021-12-28T07:22:45-05:00

The specific heat capacity of brass will be "392 J/Kg".

According to the question,

Mass of brass, \(m_{brass} = 0.59 \ kg\)
Mass of water, \(m_{water} = 2.80 \ kg\)

As we know,

→ \(m_{brass}\times c_{brass}\times \Delta T_{brass} = m_{water}\times c_{water}\times \Delta T_{water}\)

or,

→ \(c_{brass} = c_{water}\times (\frac{m_{water}}{m_{brass}} )\times (\frac{\Delta T_{water}}{\Delta T_{brass}} )\)

By substituting the above values, we get

\(= 4186\times \frac{2.8}{0.59}\times (\frac{6.8-5}{98^{\circ} C-6.8^{\circ} C} )\)

\(= 392 \ J/Kg\)

Thus the above answer is right.

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