Hi, thank you for posting your question here at Brainly.
To solve this problem, we use this equation
\(E= -E_{0} / n^{2}\), where E = 1.602E-19 Joules.
The difference of energy would then be,
\(E= E_{0}( 1/ n_{0} ^{2}+1/ n_{f} ^{2})\)
\(E= 1.602E-19( 1/ 5^{2}-1/ 1 ^{2})=-1.54E-19 Joules\)
Thus, the photon emits or releases 1.54 x 10^-19 Joules of energy.
