Use the substitution method to solve the system. {m+n=5m−n=3 What is the solution? The solution is (4, 1). There is no solution. There are an infinite number of solutions. The solution is (2, −1).
hint: \(\bf \begin{cases} m+n=5\to &m=\boxed{5-n} \\ \quad \\ \quad \\ m-n=3\to &\boxed{5-n}-n=3\quad \impliedby \textit{solve for "n"} \end{cases}\)
The value of m and n is 4 and 1. The solution is (4,1). Option A is correct.
The given system of equations is,
\(m+n=5\\m-n=3\)
It is required to solve the equations using the substitution method.
So, use the first equation to get the value of n and substitute it in the second equation as,
\(m+n=5\ =5-m\\m-n=3\\m-(5-m)=3\\2m-5=3\\2m=8\\m=4\ =5-n=5-4\ =1\)
Therefore, the value of m and n is 4 and 1. The solution is (4,1). Option A is correct.
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