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Triangle ABC is similar to triangle DEF . The length of AC is 12 cm. The length of BC is 18 cm. The length of DF is 10 cm.




What is the length of EF?

Verified Answer :

If the triangles are similar, the ratio of corresponding sides will be equal.
AC / DF = BC / EF

Substitute their values, 
12 / 10 = 18 / EF
EF = 18/12 10
EF = 3/2 10
EF = 30/2
EF = 15 cm

In short, Your Answer would be 15 cm

Hope this helps!

Triangle ABC is similar to triangle DEF. So, the length of the side EF is 15 cm and this can be determined by using the properties of similar triangle.

Given :

  • Triangle ABC is similar to triangle DEF.
  • The length of AC is 12 cm.
  • The length of BC is 18 cm.
  • The length of DF is 10 cm.

It is given that the triangle ABC and triangle DEF are similar. Therefore, the ratios of corresponding sides are also equal.

\(\rm \dfrac{AC}{DF} = \dfrac{BC}{EF}\)

Now, substitute the values of AC, DF, and BC in the above equation.

\(\rm \dfrac{12}{10} =\dfrac{18}{EF}\)

\(\rm FE = \dfrac{10\times 18}{12}\)

EF = 15 cm.

So, the length of the side EF is 15 cm.

For more information, refer to the link given below:

https://brainly.com/question/10652623

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