Answer:
The volume occupied by the air inside the hot balloon is 2.67 L.
Explanation:
Initial volume of the balloon =\(V_1= 2.50 L\)
Initial temperature of the air inside the balloon \(T_1= 22.0 °C = 295 K\)
Final volume of the balloon = \(V_2\)
Final temperature of the air inside the balloon =\(T_2= 43.0 °C = 316 K\)
Using Charles law:
\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)
\(V_2=\frac{V_1\times T_2}{T_1}=\frac{2.50 L\times 316 K}{295 K}=2.67 L\)
The volume occupied by the air inside the hot balloon is 2.67 L.
