Answer:
A
Step-by-step explanation:
Two lengths of similar figures relates by the scale factor \(k\).
Two areas of similar figures relates by the scale factor \(k^{2}\).
- If length of one figure is A, and corresponding length of another figure is B, then they are related by:
\(A=kB\)
- If area of one figure is A, and corresponding Area of another figure is B, then they are related by:
\(A=k^{2}B\)
So we can write:
\(16=k(14)\\k=\frac{16}{14}=\frac{8}{7}\)
Since, perimeter is also length, the ratio would be \(\frac{8}{7}\)
Similarly, ratio of their areas should be \(\frac{8^2}{7^2}=\frac{64}{49}\)
Answer choice A is right.
