The radius of a potassium atom is 231 pm. How many potassium atoms would have to be laid side by side to span a distance of 4.77 mm?
To determine the number of potassium laid side by side by a given distance, we simply divide the total distance to the diameter of each atom. The diameter is twice the radius of the atom. We calculate as follows:
number of atoms = 4770 / 231x10^-12 = 2.06x10^13 atoms
Answer:
2.06×\(10^{10}\) atoms
Explanation:
The radius of potassium atoms= 231 pm
convert parts per million into m i.e, by multiplying by \(10^{-6}\)
= 231×\(10^{-6}\)
Potassium atoms would have to laid down at a distance apart= 4.77 mm
convert millimeter into meter i.e, by multiplying by \(10^{-6}\)
= 4.77 ×\(10^{-6}\)
Now, we have to find the number of potassium atoms,
Number of potassium atoms=\(\frac{4.77 . 10^{-6} }{231.10^{-6} }\)
Number of potassium atoms=2.06×\(10^{10}\)
Number of potassium atoms= 2.06×\(10^{10}\) atoms
Hence, the correct answer is 2.06×\(10^{10}\) atoms