There is a common difference between terms of 5, which means the sequence is given recursively by
\(\begin{cases}a_1=-7\\a_n=a_{n-1}+5&\text{for }n>1\end{cases}\)
and explicitly by
\(a_n=-7+5(n-1)=5n-12\)
This means the 133rd term in the sequence is \(a_{133}=5(133)-12=653\)
