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Answered

To calculate the specific heat capacity of some liquid, we have poured 235 g of water at a

temperature of 18.0°C into 250 g of this liquid at a temperature of 27.0 °C in a calorimeter with a

heat capacity of 210 J/K. The temperature stabilized at 20.5 °C. Using the specific heat capacity

of water, determine the specific heat capacity of the liquid. Assume that the liquid is not soluble

in water.

Verified Answer :

MissPhiladelphia

Solve for the specific heat capacity of the liquid using this equation:

Total heat = Cp water mass water  ΔT1 + mass liquid Cp liquid  ΔT2

Heat capacity ΔTcalorimeter  = Cp water mass water  ΔT1 + mass liquid Cp liquid  ΔT2

210 J/K (27-20.5) = (235 g (18-20.5) C 4.18 J/gK) + (250 Cpliq * (27 -20.5) C )

solve for Cpliquid = 2.35 J/gK

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