The width of Quinn's tablecloth is 2.839 inch
Quinn needs to buy fabric for a border to sew onto all four edges of a tablecloth.
\(\rm Total \; amount \; of \; fabric\; needed \; f = 2(w+ \dfrac{4}{3}\times w )+ 0.875.......(1) \\\)
\(\rm Length \; of\; tablecloth = L = \dfrac{4}{3} \times w\)
According to the given condition the fabric required for potholder = 0.875 feet
Quinn needs 113/8 feet of fabric for the border of the tablecloth and the potholder.
The Total amount of fabric needed for the border and the potholder = 113/8.....(2)
So from equation (1) and (2) we get
\(\rm f = \dfrac{113}{8} \\\)
\(\rm Total \; amount \; of \; fabric\; needed \; f = 2(w+ \dfrac{4}{3}\times w )+ 0.875=\dfrac{113}{8} \\\)
Solving for w we can get
w = 2.839 inch
The width of Quinn's tablecloth is 2.839 inch
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