A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 meters. Determine the acceleration of the bike.
v^2 = 2ax
(7.10 m/s)^2 = 2a(35.4 m)
a = (7.10 m/s)^2 / (2•35.4 m)
= 0.712 m/s^2
Answer:
a = 0.712 m/s2
Explanation:
Given:
vi = 0 m/s
vf = 7.10 m/s
d = 35.4 m
Find:
a = ??
vf2 = vi2 + 2ad
(7.10 m/s)2 = (0 m/s)2 + 2(a)(35.4 m)
50.4 m2/s2 = (0 m/s)2 + (70.8 m)*a
(50.4 m2/s2)/(70.8 m) = a
a = 0.712 m/s2