10x + 5y = 80solve for y :*
\(10x+5y=80 \\ \\ (10x+5y)-10x=(80)-10x \\ \\ 5y=-10x+80 \\ \\ \frac{5y}{5}= \frac{-10x+80}{5} \\ \\ y=-2x+16\)
Write the original equation - 10x + 5y = 80
Subtract 10x from each side - 10x + 5y - 10x = 80 - 10x
Simplify - 5y = 80 - 10x
Divide each side by 5 - \(\frac{5y}{5}\) = \(\frac{80 - 10x}{5}\)
Simplify - Y = 16 - 2x
